#include <stdio.h>
char INPUT[102][102];
int search(int I, int J, char *Q, int *LI, int *LJ) {
int X_D[9] = { 0, -1, -1, -1, 0, 1, 1, 1};
int Y_D[9] = {-1, -1, 0, 1, 1, 1, 0, -1};
int X, Y, T, S;
for (T=0 ; T<8 ; T++) {
for (X=I, Y=J, S=0 ; Q[S]!='\0' ; S++) {
if (INPUT[X][Y]!=Q[S]) {
break;
} else {
X+=X_D[T];
Y+=Y_D[T];
}
}
if (Q[S]=='\0') {
*LI = X-X_D[T];
*LJ = Y-Y_D[T];
return 1;
}
}
return 0;
}
int main() {
int L, I, J, LI, LJ, FOUND;
char Q[102];
scanf("%d",&L);
for (I=0 ; I<L ; I++) {
scanf("%s",INPUT[I]);
}
while(scanf("%s",Q)==1) {
if (!strcmp(Q,"0"))
break;
for (I=0, FOUND=0 ; I<L && !FOUND ; I++) {
for (J=0 ; J<L ; J++) {
if(INPUT[I][J]==Q[0]) {
if (search(I,J,Q,&LI,&LJ)) {
printf("%d,%d %d,%d\n",I+1, J+1, LI+1, LJ+1);
FOUND = 1;
break;
}
}
}
}
if (!FOUND)
printf("Not found\n");
}
return 0;
}
Wednesday, September 08, 2010
[UVa] 422 - Word Search Wonders
Just brute-force through the matrix and you're done. Using an array for the directions to move in will decrease the amount of coding significantly.
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