#include <stdio.h>
#include <math.h>
#include <string.h>
int primes[7000];
bool marks[60000];
int sieve2(int n)
{
int i, j, k;
memset(marks,true,n);
marks[0] = marks[1] = false;
for (i=4 ; i<n ; i+=2)
marks[i]=false;
for (i=3 ; i*i<n ; i+=2)
{
if (marks[i]==true)
{
for (j=i*i ; j<n ; j+=(2*i))
marks[j]=false;
}
}
for (i=2, j=0 ; i<=n ; i++)
{
if (marks[i]==true)
{
primes[j++]=i;
}
}
return j-1;
}
int main() {
int i, j, kounter=0, q;
int mark=sieve2(50000);
while (scanf("%d",&q) && q)
{
kounter=0;
printf("%d : ",q);
for (j=0 ; primes[j]<q && j<mark ; j++)
{
if (q%primes[j]==0) kounter++;
while (q%primes[j]==0)
{
q/=primes[j];
}
}
if (q>1)
kounter++;
printf("%d\n",kounter);
}
return 0;
}
Saturday, September 04, 2010
[UVa] 10699 - Count the Factors
It's a slight modification of the code I used for 583. Simple enough.
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